A cheetah is hunting. Its prey runs for 7.4 s at a constant velocity of 11.3 m/s. Starting from rest, what constant acceleration must the cheetah maintain in order to run the same distance as its prey in the same time?

x = v t x = a t 2 v t = a t 2 v = a t a = t v ​ = 7.4 11.3 ​ = 1.527 m / s 2

Answered by Anonymous | 2024-06-10

To catch its prey, the cheetah must maintain a constant acceleration of approximately 3.05 m/s². This is calculated by first determining the distance covered by the prey and applying the equations of motion for the cheetah starting from rest. Setting the distances equal allows us to solve for the required acceleration.
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Answered by Anonymous | 2024-10-02