1 BAG= 4/6 days which is 2/3 4 BAGS= 6 days ? BAGS= 9 days 9 days =2/3 X 9 days therefore 2 X 3 =6 BAGS therefore 6bags = 9days
1 BAG= 4/6 days which is 2/3
4 BAGS= 6 days
? BAGS= 9 days
9 days =2/3 X 9 days
therefore 2 X 3 =6 BAGS
therefore 6bags = 9days
You need 6 bags of corn to feed the herd for 9 days. This is calculated by determining that 4 bags feed the herd for 6 days, which translates to each day requiring 2/3 of a bag. Multiplying this by 9 days gives you a total of 6 bags needed.
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