Justin is redoing his bathroom floor with tiles measuring 6 in by 13 in. The floor has an area of 8,500 in². What is the least number of tiles he will need?

a re a o f f l oor : A = 8500 i n 2 T i l es : 6 in x 13 in A re a o f o n e t i l e : A t ​ = 6 ∗ 13 = 78 i n 2 N u mb er o f t i l es : A t ​ A ​ = 78 8500 ​ = 108 , 9 ≈ 109 He \ w i ll n ee d 109 t i l es .

Answered by luana | 2024-06-10

To cover a floor of 8,500 in² with 6in by 13in tiles, calculate the area of one tile (78 in²) and divide the total floor area by the area of one tile, resulting in approximately 108.97 tiles. Needing whole tiles, Justin will require at least 109 tiles. ;

Answered by kesarineha07 | 2024-06-24

Justin will need a minimum of 109 tiles to cover the bathroom floor. This is calculated by dividing the total area of the floor (8500 in²) by the area of one tile (78 in²) and rounding up to the nearest whole number. Therefore, at least 109 tiles are required for the job.
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Answered by luana | 2024-10-02