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Questions in Grade High-school

[Answered] $f(f(x)) = 6x - 4$. What is $f(2)$?

[Answered] Which are difficulties translators face when working with Beowulf? Select all that apply. accurately recreating Old English word order accurately compressing Old English narrative sequences accurately avoiding Old English literary devices accurately representing Old English poetic rhythms and meters

[Answered] [tex]\frac{2}{7} x+\frac{1}{7}=-\frac{5}{7}[/tex]

[Answered] Solve the inequality. Express your answer using set notation and interval notation. [tex]0 \leq 3 x-9 \leq 15[/tex] The solution is expressed in set notation as [tex] \{x \mid[/tex] [$\square$\}]. The solution is expressed in interval notation as [$\square$].

[Answered] Find the mean deviation about the median for the following data: (a) \begin{tabular}{|c|c|c|c|c|c|} \hline$x$ & 15 & 21 & 27 & 30 & 35 \\ \hline$f$ & 3 & 5 & 6 & 7 & 8 \\ \hline \end{tabular} (b) \begin{tabular}{|c|c|c|c|c|c|c|c|} \hline$x$ & 5 & 7 & 9 & 11 & 13 & 15 & 17 \\ \hline$f$ & 2 & 4 & 6 & 8 & 10 & 12 & 8 \\ \hline \end{tabular} (c) \begin{tabular}{|c|c|c|c|c|c|c|c|c|} \hline$x$ & 10 & 15 & 20 & 25 & 30 & 35 & 40 & 45 \\ \hline$f$ & 7 & 3 & 8 & 5 & 6 & 8 & 4 & 9 \\ \hline \end{tabular}

[Answered] Solve $2(1-x)+3=-8$. Check your solution.

[Answered] What is [tex]$\left(\frac{1}{7}\right)^3$[/tex] equal to? A. [tex]$\frac{1}{10}$[/tex] B. [tex]$\frac{3}{21}$[/tex] C. [tex]$\frac{1}{343}$[/tex] D. [tex]$\frac{3}{2401}$[/tex]

[Answered] (3) [tex]\frac{2^9}{2^5}[/tex]

[Answered] Convert the point-slope form below to slope-intercept form and identify the key features. [tex]y+10=-5(3 x+5)[/tex] Answers must be written as proper fractions, improper fractions, or integers. Slope: [ ] y-intercept: [ ]

[Answered] Write the domain in interval notation of each function: a. [tex]$y=x^2+7$[/tex] b. [tex]$g(x)=\frac{3 x-2}{(x+6)(x-4)}$[/tex] c. [tex]$f(x)=\sqrt{x-2}$[/tex] d. [tex]$y=\frac{1}{\sqrt{5-x}}$[/tex] e. [tex]$h(x)=\frac{x}{x^2-2 x}$[/tex] f. [tex]$f(x)=\frac{5}{x+4}-\frac{2}{x}$[/tex] g. [tex]$y=\frac{1}{x^2+6}$[/tex] h. [tex]$g(x)=\frac{\sqrt{8-x}}{(x+4)\left(x^2+1\right)}$[/tex]