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Questions in mathematics
[Answered] 1. Add the following: a. 13,65,042 + 11,31,741 b. 12,12,900 + 40,56,062 c. 41,22,692 + 3,54,55,201 d. 78,23,455 + 2,21,56,222 e. 4,01,89,856 + 8,54,45,971 f. 7,59,72,298 + 2,67,88,701 g. 5,68,78,585 + 63,58,868 h. 4,99,23,858 + 7,84,10,864 2. Subtract the following: a. 85,53,487 - 41,21,277 b. 98,44,885 - 87,62,152 c. 8,83,91,895 - 7,61,10,584 d. 6,89,92,292 - 4,78,81,161 e. 5,33,03,543 - 2,34,67,343 f. 30,18,391 - 19,98,899 g. 6,08,08,292 - 2,87,09,523 h. 7,25,55,852 - 1,26,88,643 3. Solve the following: a. 16,75,994 + 1,21,333 - 76,223 b. 53,409 + 1,12,763 - 12,856 c. 1,17,77,909 - 6,21,008 + 1,21,568 d. 8,71,004 - 71,005 + 52,646 e. 25,42,734 + 76,999 - 87,444 f. 16,11,006 - 1,61,843 + 2,42,0
[Answered] Calculate the product of 5789 and 28. 5789 × 28
[Answered] Now, using the information about the breakfasts that some students have in the morning, find the ratio of students who ate cereal to those who ate yoghurt. Give your answer in its simplest form. | | Porridge | Cereal | Toast | Yoghurt | Total | | --------- | -------- | ------ | ----- | ------- | ----- | | Class A | 6 | 13 | 4 | 6 | 29 | | Class B | 2 | 8 | 7 | 11 | 28 | | Class C | 4 | 6 | 6 | 7 | 23 | | Total | 12 | 27 | 17 | 24 | 80 |
[Answered] $\frac{2}{7} \times\left[\frac{7}{16}-\frac{21}{4}\right]$
[Answered] Add. Write your answer in simplest form. $8 \sqrt{63}+10 \sqrt{7}$
[Answered] For [tex]f(x)=2 x+1[/tex] and [tex]g(x)=x^2-7[/tex], find [tex]\left(\frac{g}{f}\right)(x)[/tex]. A. [tex]\frac{2 x+1}{x^2-7}, x \neq \pm \sqrt{7}[/tex] B. [tex]\frac{2 x+1}{x^2-7}[/tex] C. [tex]\frac{x^2-7}{2 x+1}[/tex] D. [tex]\frac{x^2-7}{2 x+1}, x=-\frac{1}{2}[/tex]
[Answered] Simplify $(6^{1 / 9})^4$. A. $6^{16}$ B. 1 C. $6^4$ D. 6
[Answered] Which expressions are equivalent to $\sqrt[3]{128}^x$ ? Select three correct answers. $128^{\frac{x}{3}}$ $128^{\frac{3}{x}}$ $(4 \sqrt[3]{2})^x$ $\left(4\left(2^{\frac{1}{3}}\right)\right)^x$ $(2 \sqrt[3]{4})^x$
[Answered] The diameter of a large lawn ornament in the shape of a sphere is 16 inches. What is the approximate volume of the ornament? Use 3.14 for [tex]$\pi$[/tex]. Round to the nearest tenth of a cubic inch. Recall the formula Sphere [tex]$V=\frac{4}{3} \pi r^3$[/tex].
[Answered] Which expressions are equal to [tex]$\sum_{n=1}^{50} n(n+6)$[/tex]? Check all that apply. [tex]$\sum_{n=1}^{50} n+\sum_{n=1}^{50}(n+6)$[/tex] [tex]$\sum_{n=1}^{50} n^2+\sum_{n=1}^{50} 6 n$[/tex] [tex]$\sum_{n=1}^{50} n \times \sum_{n=1}^{50}(n+6)$[/tex] [tex]$\sum_{n=1}^{50} n^2+6 \sum_{n=1}^{50} n$[/tex]
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