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Questions in mathematics

[Answered] $28 \overline{)735}$

[Answered] Drag the tiles to the correct boxes to complete the pairs. Match each equation with its solution. [tex] \begin{array}{c} e^{x^2}=e^{4 x+5} \ \ln (x+5)=\ln (x-1)+\ln (x+1) \ \log _4\left(5 x^2+2\right)=\log _4(x+8) \ -1 \text { and } 5 \longrightarrow \ \text { only } 3 \end{array} [/tex]

[Answered] Question 11: Two 10 meter tall poles are 30 meters apart. A length of wire is attached to the top of each pole and it is staked to the ground somewhere between the two poles. Where should the wire be staked so that the minimum amount of wire is used? Question 13. Use differently and the formula [tex]$\overline{L(x)}-\int(a)+\int^{\prime}(a)(x-a)$[/tex] to approximate [tex]$\sqrt[3]{50}$[/tex]. To do this, complete the following steps: a) Find the function [tex]$f(x)=[/tex] b) The point [tex]$a=[/tex] c) The point [tex]$x=[/tex] d) The derivative [tex]$f^{\prime}(a)=[/tex] e) [tex]$\sqrt[3]{50} \approx L(x)=[/tex]

[Answered] 0=-4 x^6-3 x^5+2 x^2-4 x+1 ? Drag the choices to the boxes to correctly complete the table.

[Answered] Add: $6 u^9+\left(8 u^9+4 v\right)$

[Answered] $65 \overline{)99,521}$

[Answered] Find the value of [tex]$x$[/tex] and [tex]$YZ$[/tex] if [tex]$Y$[/tex] is between [tex]$X$[/tex] and [tex]$Z$[/tex]. [tex]$XY=4x, YZ=3x$[/tex], and [tex]$XZ=42$[/tex] [tex]$x=$[/tex] $\square$ ; [tex]$YZ=$[/tex] $\square$

[Answered] Question 4: The radius of a sphere is increased from 10 cm to 10.1 cm. Estimate the change in volume. (10 pts) a) [tex]$\Delta V \approx 36 \pi cm^3$[/tex] b) [tex]$\Delta V \approx 38 \pi cm^3$[/tex] c) [tex]$\Delta V \approx 10 \pi cm^3$[/tex] d) [tex]$\Delta V \approx 42 \pi cm^3$[/tex]

[Answered] Write the equation of the line tangent to [tex]f(x)=\cos x[/tex] when [tex]x=\frac{3 \pi}{2}[/tex] a.) [tex]y=x-\frac{3 \pi}{2}[/tex] b.) [tex]y=-x+\frac{3 \pi}{2}[/tex] c.) [tex]y=-x-\frac{3 \pi}{2}[/tex] d.) [tex]y=x+\frac{3 \pi}{2}[/tex]

[Answered] Find the square root of each number. [tex]\begin{array}{l} \sqrt{81}=\square \ \sqrt{169}=\square \end{array}[/tex]