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Questions in mathematics

[Answered] $f(f(x)) = 6x - 4$. What is $f(2)$?

[Answered] Solve $81^x=27^{x+2}$.

[Answered] [tex]\frac{2}{7} x+\frac{1}{7}=-\frac{5}{7}[/tex]

[Answered] For $y=x^2-5 x+6$, determine the vertex, axis of symmetry, domain, and range. Vertex: Axis of Symmetry: Domain: Range:

[Answered] Solve the inequality. Express your answer using set notation and interval notation. [tex]0 \leq 3 x-9 \leq 15[/tex] The solution is expressed in set notation as [tex] \{x \mid[/tex] [$\square$\}]. The solution is expressed in interval notation as [$\square$].

[Answered] Darryl wants to add enough water to 8 gallons of a $10 \%$ bleach solution to make a $5 \%$ bleach solution. Which equation can he use to find $x$, the number of gallons of water he should add? Original (Gallons) Added (Gallons) New (Gallons) Amount of Bleach & 0.8 & 0 & 0.8 Amount of Solution & 8 & $x$ & $8+x$ $\left(\frac{0.8}{8+x}\right)\left(\frac{5}{100}\right)=1$ $\frac{0.8}{8+x}=\frac{5}{100}$ $\frac{0.8}{8+x}=\frac{100}{5}$ $\frac{10}{1} \quad \frac{5}{00}=1$

[Answered] Select the correct answer. One factor of the polynomial [tex]$6 x^3-x^2+8 x+5$[/tex] is [tex]$(2 x+1)$[/tex]. What is the other factor of the polynomial? (Note: Use long division.) A. [tex]$\left(3 x^2+5\right)$[/tex] B. [tex]$\left(3 x^2-2\right)$[/tex] C. [tex]$\left(3 x^2-2 x+5\right)$[/tex] D. [tex]$\left(3 x^2+5 x-2\right)$[/tex]

[Answered] Consider the function [tex]f(x)=3 x^2-5 x+2[/tex]. Use it to find [tex]f(4), f(-1)[/tex], and [tex]f(a+3)[/tex]. A. [tex] \begin{array}{l} f(4)=30 \\ f(-1)=10 \\ f(a+3)=3 a^2+13 a+14 \end{array} [/tex] B. [tex] \begin{array}{l} f(4)=126 \\ f(-1)=3 \\ f(a+3)=9 a^2-5 a+14 \end{array} [/tex] C. [tex] \begin{array}{l} f(4)=30 \\ f(-1)=9 \\ f(a+3)=9 a^2-5 a+14 \end{array} [/tex] D. [tex] \begin{array}{l} f(4)=30 \\ f(-1)=-6 \\ f(a+3)=3 a^2+13 a+14 \end{array} [/tex]

[Answered] Find the mean deviation about the median for the following data: (a) \begin{tabular}{|c|c|c|c|c|c|} \hline$x$ & 15 & 21 & 27 & 30 & 35 \\ \hline$f$ & 3 & 5 & 6 & 7 & 8 \\ \hline \end{tabular} (b) \begin{tabular}{|c|c|c|c|c|c|c|c|} \hline$x$ & 5 & 7 & 9 & 11 & 13 & 15 & 17 \\ \hline$f$ & 2 & 4 & 6 & 8 & 10 & 12 & 8 \\ \hline \end{tabular} (c) \begin{tabular}{|c|c|c|c|c|c|c|c|c|} \hline$x$ & 10 & 15 & 20 & 25 & 30 & 35 & 40 & 45 \\ \hline$f$ & 7 & 3 & 8 & 5 & 6 & 8 & 4 & 9 \\ \hline \end{tabular}

[Answered] Solve $2(1-x)+3=-8$. Check your solution.